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Popular >

extreme y=x^3+3x^2+3x+1

Solution

extreme points

y = x^{3} + 3 x^{2} + 3 x + 1

Solution

Saddle (- 1, 0)

Solution steps

f^{'} (x) = 3 x^{2} + 6 x + 3

Find intervals:

Increasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

x^{3} + 3 x^{2} + 3 x + 1 : 0

Saddle (- 1, 0)

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extreme f(x)=6x+6/x extreme points

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extreme f(x,y)=x^2-3xy-y^2 extreme points

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Frequently Asked Questions (FAQ)

What is the extreme y=x^3+3x^2+3x+1 ?
The extreme y=x^3+3x^2+3x+1 is Saddle(-1,0)