What is the extreme p(x)=12x^4-27x^3+ax^2+27x-6 ?

The extreme p(x)=12x^4-27x^3+ax^2+27x-6 is None

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extreme p(x)=12x^4-27x^3+ax^2+27x-6

extreme points

p (x) = 12 x^{4} - 27 x^{3} + a x^{2} + 27 x - 6

None

Solution steps

Find the critical points:

None

12 x^{4} - 27 x^{3} + a x^{2} + 27 x - 6

has no critical points, therefore there are no extreme points

None

f (x, y) = x^{3} - 3 x + y^{2} + 6 y + 8

f (x, y) = 8 + 76 x y + 38 x^{2} + 240 y + \frac{y ^{4}}{4}

y = \frac{x ^{2}}{ln ( x )}

f (x) = x^{3} - 6 x^{2} + 9 + 9, - 1 \leq x \leq 9

f (x, y) = 16 - x^{2} - 16 y^{2}

What is the extreme p(x)=12x^4-27x^3+ax^2+27x-6 ?
The extreme p(x)=12x^4-27x^3+ax^2+27x-6 is None