What is the extreme f(x)=(-3x^2y+9xy^2-12xy)/(xy) ?

The extreme f(x)=(-3x^2y+9xy^2-12xy)/(xy) is None

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extreme f(x)=(-3x^2y+9xy^2-12xy)/(xy)

extreme points

f (x) = \frac{- 3 x ^{2} y + 9 x y ^{2} - 12 x y}{x y}

None

Solution steps

Find the critical points:

None

\frac{- 3 x ^{2} y + 9 x y ^{2} - 12 x y}{x y}

has no critical points, therefore there are no extreme points

None

f (x) = - 3 + 8 x - x^{3}

f (x) = \frac{x + 1}{x ^{2} - 2 x - 3}

f (x, y) = 7 x^{2} - 10 y^{2}

y = \frac{3 x}{x ^{2} - 1}

x^{3} + 6 x^{2} + 12 x + 7

What is the extreme f(x)=(-3x^2y+9xy^2-12xy)/(xy) ?
The extreme f(x)=(-3x^2y+9xy^2-12xy)/(xy) is None