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Popular >

extreme f(x)=2x^3-6x^2+6x+1

Solution

extreme points

f (x) = 2 x^{3} - 6 x^{2} + 6 x + 1

Solution

Saddle (1, 3)

Solution steps

f^{'} (x) = 6 x^{2} - 12 x + 6

Find intervals:

Increasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

2 x^{3} - 6 x^{2} + 6 x + 1 : 3

Saddle (1, 3)

Popular Examples

extreme f(x)=(x+3)-5 extreme points

f (x) = (x + 3) - 5

extreme f(x)= 1/3 x^3-7/2 x^2+6x+1 extreme points

f (x) = \frac{1}{3} x^{3} - \frac{7}{2} x^{2} + 6 x + 1

extreme f(x,y)=e^{x^2+1}+e^{y^2+1}extreme points

f (x, y) = e^{x^{2} + 1} + e^{y^{2} + 1}

extreme f(x)=(2x^2+5)/(x^2-25)extreme points

f (x) = \frac{2 x ^{2} + 5}{x ^{2} - 25}

extreme f(x,y)=x-5y+6 extreme points

f (x, y) = x - 5 y + 6

Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^3-6x^2+6x+1 ?
The extreme f(x)=2x^3-6x^2+6x+1 is Saddle(1,3)