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Popular >

extreme y=(x+3)^2-7

Solution

extreme points

y = (x + 3)^{2} - 7

Solution

Minimum (- 3, - 7)

Solution steps

f^{'} (x) = 2 x + 6

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: - 3 < x < \infty

Plug

x = - 3

into

(x + 3)^{2} - 7 : - 7

Minimum (- 3, - 7)

Popular Examples

extreme f(x)=3x-1/2 x^2-1/2 ln(x)extreme points

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extreme f(x)=20.85xy+10.7x^2+51.75y^2 extreme points

f (x) = 20.85 x y + 10.7 x^{2} + 51.75 y^{2}

extreme x^5-x^3 extreme points

x^{5} - x^{3}

extreme f(x)=6sin(2x)extreme points

f (x) = 6 sin (2 x)

extreme x^2+2x+6 extreme points

x^{2} + 2 x + 6

Frequently Asked Questions (FAQ)

What is the extreme y=(x+3)^2-7 ?
The extreme y=(x+3)^2-7 is Minimum(-3,-7)