What is the extreme f(x,y)=x^2-xy+y^2-2y+xp(1.1) ?

The extreme f(x,y)=x^2-xy+y^2-2y+xp(1.1) is Minimum((-11p+10)/(15),(40-11p)/(30))

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extreme f(x,y)=x^2-xy+y^2-2y+xp(1.1)

extreme points

f (x, y) = x^{2} - x y + y^{2} - 2 y + x p (1.1)

Minimum (\frac{- 11 p + 10}{15}, \frac{40 - 11 p}{30})

Solution steps

Find the critical points:

(\frac{- 11 p + 10}{15}, \frac{40 - 11 p}{30})

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = 3

Check the sign of at each critical point

Check critical point

(\frac{- 11 p + 10}{15}, \frac{40 - 11 p}{30}) :

Minimum

Minimum (\frac{- 11 p + 10}{15}, \frac{40 - 11 p}{30})

2 x^{2} - 8 x y + 10 y^{2} + 10 x - 4 y - 5

f (x) = \frac{2 x}{x ^{2} + 2}

ln (2 x - 3) - ln (x + 5) + 1

f (x) = 3 + 6 x^{2} - 4 x^{3}

f (x, y) = x^{2}

What is the extreme f(x,y)=x^2-xy+y^2-2y+xp(1.1) ?
The extreme f(x,y)=x^2-xy+y^2-2y+xp(1.1) is Minimum((-11p+10)/(15),(40-11p)/(30))