What is the extreme f(x)=2x^2ln(x)-5x^2 ?

The extreme f(x)=2x^2ln(x)-5x^2 is Minimum(e^2,-e^4)

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extreme f(x)=2x^2ln(x)-5x^2

extreme points

f (x) = 2 x^{2} ln (x) - 5 x^{2}

Minimum (e^{2}, - e^{4})

Solution steps

f^{'} (x) = 4 x (ln (x) - 2)

Find intervals:

Decreasing

: 0 < x < e^{2},

Increasing

: e^{2} < x < \infty

Plug

x = e^{2}

into

2 x^{2} ln (x) - 5 x^{2} : - e^{4}

Minimum (e^{2}, - e^{4})

f (x, y) = ln (2 x + y) - x^{2} - 3 y

f (x, y) = ln (2 x + y) - x^{2} - 4 y

U (X, Y) = X^{0.4} Y^{0.6}

f (x) = \frac{2 x + 4}{x + 1}

pp + qq

What is the extreme f(x)=2x^2ln(x)-5x^2 ?
The extreme f(x)=2x^2ln(x)-5x^2 is Minimum(e^2,-e^4)