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Popular >

extreme f(x)=(3x^3-9)

Solution

extreme points

f (x) = (3 x^{3} - 9)

Solution

Saddle (0, - 9)

Solution steps

f^{'} (x) = 9 x^{2}

Find intervals:

Increasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

3 x^{3} - 9 : - 9

Saddle (0, - 9)

Popular Examples

extreme f(x)=(x^2-4)/(e^{x^4-1)}extreme points

f (x) = \frac{x ^{2} - 4}{e ^{x^{4} - 1}}

extreme f(x)=2x-5x^2+4 extreme points

f (x) = 2 x - 5 x^{2} + 4

extreme f(x)=(4x)/(x^2+16)extreme points

f (x) = \frac{4 x}{x ^{2} + 16}

extreme f(x,y)=x^4+y^4-4xy+x extreme points

f (x, y) = x^{4} + y^{4} - 4 x y + x

extreme-2x^3+14x^2+2y^2+4xy extreme points

- 2 x^{3} + 14 x^{2} + 2 y^{2} + 4 x y

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(3x^3-9) ?
The extreme f(x)=(3x^3-9) is Saddle(0,-9)