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Popular >

extreme f(x)=x^2-12x+36

Solution

extreme points

f (x) = x^{2} - 12 x + 36

Solution

Minimum (6, 0)

Solution steps

f^{'} (x) = 2 x - 12

Find intervals:

Decreasing

: - \infty < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 6

into

x^{2} - 12 x + 36 : 0

Minimum (6, 0)

Popular Examples

extreme f(x)=x(21-37+2x)(37/2-x)extreme points

f (x) = x (21 - 37 + 2 x) (\frac{37}{2} - x)

extreme f(x)=4x^4-2x^3-7x^2+3x+1 extreme points

f (x) = 4 x^{4} - 2 x^{3} - 7 x^{2} + 3 x + 1

extreme f(x)=x^3+10x+21 extreme points

f (x) = x^{3} + 10 x + 21

extreme (2x)/3-17 extreme points

\frac{2 x}{3} - 17

extreme y=(3x)/(x^2-16)extreme points

y = \frac{3 x}{x ^{2} - 16}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-12x+36 ?
The extreme f(x)=x^2-12x+36 is Minimum(6,0)