What is the extreme f(x)=2x^2(x^2-2) ?

The extreme f(x)=2x^2(x^2-2) is Minimum(-1,-2),Maximum(0,0),Minimum(1,-2)

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extreme f(x)=2x^2(x^2-2)

extreme points

f (x) = 2 x^{2} (x^{2} - 2)

Minimum (- 1, - 2), Maximum (0, 0), Minimum (1, - 2)

Solution steps

f^{'} (x) = 2 (4 x^{3} - 4 x)

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 0,

Decreasing

: 0 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

2 x^{2} (x^{2} - 2) : - 2

Minimum (- 1, - 2)

Plug

x = 0

into

2 x^{2} (x^{2} - 2) : 0

Maximum (0, 0)

Plug

x = 1

into

2 x^{2} (x^{2} - 2) : - 2

Minimum (1, - 2)

Minimum (- 1, - 2), Maximum (0, 0), Minimum (1, - 2)

- 3 x + ln (x)

f (x) = 52 (70 - x)

f (x) = x^{11} - 9 x^{7} + 5 x - 3

f (x) = x^{2} + y^{2} - 2 x - 2 y + 3

f (x) = 2 x^{2} + 3 x - 1

What is the extreme f(x)=2x^2(x^2-2) ?
The extreme f(x)=2x^2(x^2-2) is Minimum(-1,-2),Maximum(0,0),Minimum(1,-2)