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Popular >

extreme f(x)=x^2-12x+5

Solution

extreme points

f (x) = x^{2} - 12 x + 5

Solution

Minimum (6, - 31)

Solution steps

f^{'} (x) = 2 x - 12

Find intervals:

Decreasing

: - \infty < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 6

into

x^{2} - 12 x + 5 : - 31

Minimum (6, - 31)

Popular Examples

extreme f(x)=x^2-y^2+21 extreme points

f (x) = x^{2} - y^{2} + 21

extreme f(x,y)=(9x^2+4x+5)(9y^2+6y+6)extreme points

f (x, y) = (9 x^{2} + 4 x + 5) (9 y^{2} + 6 y + 6)

extreme f(x)=6x^3-x^2-5x+7 extreme points

f (x) = 6 x^{3} - x^{2} - 5 x + 7

extreme f(x)=γ(x+1)extreme points

f (x) = γ (x + 1)

extreme f(x)= x/(x^2-64)extreme points

f (x) = \frac{x}{x ^{2} - 64}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-12x+5 ?
The extreme f(x)=x^2-12x+5 is Minimum(6,-31)