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Popular >

extreme f(x)=x^2-2x+5[-1.4]

Solution

extreme points

f (x) = x^{2} - 2 x + 5 [- 1.4]

Solution

Minimum (1, - 8)

Solution steps

f^{'} (x) = 2 x - 2

Find intervals:

Decreasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

x^{2} - 2 x + 5 [- 1.4] : - 8

Minimum (1, - 8)

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2 x^{4} - 196 x^{2} - 3

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extreme f(t)=4t^3-36t^2+10,t>= 0 extreme points

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-2x+5[-1.4] ?
The extreme f(x)=x^2-2x+5[-1.4] is Minimum(1,-8)