What is the extreme f(x,y)=-3x^2-2y^2+24x+20y+600 ?

The extreme f(x,y)=-3x^2-2y^2+24x+20y+600 is Maximum(4,5)

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extreme f(x,y)=-3x^2-2y^2+24x+20y+600

extreme points

f (x, y) = - 3 x^{2} - 2 y^{2} + 24 x + 20 y + 600

Maximum (4, 5)

Solution steps

Find the critical points:

(4, 5)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 4

D (x, y) = 24

Check the sign of at each critical point

Check critical point

(4, 5) :

Maximum

Maximum (4, 5)

f (x) = 5 (\frac{1}{x - 4} - \frac{1}{x + 2})

\frac{x ^{3} - 4 x ^{2}}{x ^{2} + 1}

f (x) = 10 + 5 x - x^{2}

f (x) = 2 x^{2} n x - 19 x^{2}

f (x, y, z) = - x^{2} - 3 y^{2} + 4 x - 6 y - 5

What is the extreme f(x,y)=-3x^2-2y^2+24x+20y+600 ?
The extreme f(x,y)=-3x^2-2y^2+24x+20y+600 is Maximum(4,5)