What is the extreme f(x)=2x^3-6x+11 ?

The extreme f(x)=2x^3-6x+11 is Maximum(-1,15),Minimum(1,7)

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extreme f(x)=2x^3-6x+11

extreme points

f (x) = 2 x^{3} - 6 x + 11

Maximum (- 1, 15), Minimum (1, 7)

Solution steps

f^{'} (x) = 6 x^{2} - 6

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

2 x^{3} - 6 x + 11 : 15

Maximum (- 1, 15)

Plug

x = 1

into

2 x^{3} - 6 x + 11 : 7

Minimum (1, 7)

Maximum (- 1, 15), Minimum (1, 7)

f (x) = sin (5 x), 0 \leq x \leq \frac{2 π}{5}

y = 16 x^{4} + 64 x^{3}

3 x^{2} - 2 x y + y^{2} - 8 y

f (x) = 32 e^{4 x} x - 28 e^{4 x}

f (x) = 12 x - 9 x^{2} + 2 x^{3}

What is the extreme f(x)=2x^3-6x+11 ?
The extreme f(x)=2x^3-6x+11 is Maximum(-1,15),Minimum(1,7)