What is the extreme f(x)=((x^2-1))/(x^2+2x-3) ?

The extreme f(x)=((x^2-1))/(x^2+2x-3) is None

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extreme f(x)=((x^2-1))/(x^2+2x-3)

extreme points

f (x) = \frac{( x ^{2} - 1 )}{x ^{2} + 2 x - 3}

None

Solution steps

f^{'} (x) = \frac{2}{( x + 3 ) ^{2}}

Find intervals:

None

None

f (x) = - 3 t^{2} + 72 t + 243

y = - 2 x^{2} e^{- 2 x} - 2

f (x) = x (22 - 37 + 2 x) (\frac{37}{2} - x)

f (x) = x^{8} e^{x} - 5

f (x) = \frac{1}{2} x e^{- 5 x^{2}}

What is the extreme f(x)=((x^2-1))/(x^2+2x-3) ?
The extreme f(x)=((x^2-1))/(x^2+2x-3) is None