What is the range of f(x)=(x+3)/(x+6) ?

The range of f(x)=(x+3)/(x+6) is f(x) 1

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range of f(x)=(x+3)/(x+6)

range

f (x) = \frac{x + 3}{x + 6}

f (x) < 1 or f (x) > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{x + 3}{x + 6}

Inverse of

\frac{x + 3}{x + 6} : \frac{3 - 6 x}{x - 1}

\frac{3 - 6 x}{x - 1}

Find the domain of each inverse function

Domain of

\frac{3 - 6 x}{x - 1} : x < 1 or x > 1

Combine the intervals

f (x) < 1 or f (x) > 1

f (x) = 7 x

7 c - 14

f (x) = \frac{( 2 x ^{2} - x - 10 )}{x + 2}

f (x) = 1 - 2^{x}

f (x) = 2 (ln (x) + 1)

What is the range of f(x)=(x+3)/(x+6) ?
The range of f(x)=(x+3)/(x+6) is f(x)<1\lor f(x)>1