What is the extreme f(x)=(x+10)((60)/x+6) ?

The extreme f(x)=(x+10)((60)/x+6) is Maximum(-10,0),Minimum(10,240)

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extreme f(x)=(x+10)((60)/x+6)

extreme points

f (x) = (x + 10) (\frac{60}{x} + 6)

Maximum (- 10, 0), Minimum (10, 240)

Solution steps

f^{'} (x) = - \frac{600}{x ^{2}} + 6

Find intervals:

Increasing

: - \infty < x < - 10,

Decreasing

: - 10 < x < 0,

Decreasing

: 0 < x < 10,

Increasing

: 10 < x < \infty

Plug

x = - 10

into

(x + 10) (\frac{60}{x} + 6) : 0

Maximum (- 10, 0)

Plug

x = 10

into

(x + 10) (\frac{60}{x} + 6) : 240

Minimum (10, 240)

Maximum (- 10, 0), Minimum (10, 240)

f (x) = \frac{1}{2} x^{4} - 4 x^{2} + 5

f (x) = \frac{1}{2} x^{4} - 4 x^{2} + 3

f (x) = - 3 x^{2} + 180 x + 190, 0 \leq x \leq 40

f (x) = (x + 2)^{\frac{2}{3}} (x - 2)^{\frac{1}{3}}

f (x) = - x^{3} - 6 x^{2} + 6

What is the extreme f(x)=(x+10)((60)/x+6) ?
The extreme f(x)=(x+10)((60)/x+6) is Maximum(-10,0),Minimum(10,240)