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Popular >

extreme ln(x^2+7)

Solution

extreme points

ln (x^{2} + 7)

Solution

Minimum (0, ln (7))

Solution steps

f^{'} (x) = \frac{2 x}{x ^{2} + 7}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

ln (x^{2} + 7) : ln (7)

Minimum (0, ln (7))

Graph

Popular Examples

extreme f(x)=3x^5-20x^3+42 extreme points

f (x) = 3 x^{5} - 20 x^{3} + 42

extreme f(x,y)=3x^2-y^2-7x-y+8 extreme points

f (x, y) = 3 x^{2} - y^{2} - 7 x - y + 8

extreme f(x)=2+28x-2x^2 extreme points

f (x) = 2 + 28 x - 2 x^{2}

extreme f(x)=2x^3-x^2-4x+10,-1<= x<= 0 extreme points

f (x) = 2 x^{3} - x^{2} - 4 x + 10, - 1 \leq x \leq 0

extreme f(x)=-4/3 x^{3/4}extreme points

f (x) = - \frac{4}{3} x^{\frac{3}{4}}

Frequently Asked Questions (FAQ)

What is the extreme ln(x^2+7) ?
The extreme ln(x^2+7) is Minimum(0,ln(7))