en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme ln(x^2+4)

Solution

extreme points

ln (x^{2} + 4)

Solution

Minimum (0, 2 ln (2))

Solution steps

f^{'} (x) = \frac{2 x}{x ^{2} + 4}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

ln (x^{2} + 4) : 2 ln (2)

Minimum (0, 2 ln (2))

Popular Examples

extreme f(x)=x^4-32x^2+10 extreme points

f (x) = x^{4} - 32 x^{2} + 10

extreme f(x)=x^3+y^3+3x^2-9y^2-1 extreme points

f (x) = x^{3} + y^{3} + 3 x^{2} - 9 y^{2} - 1

extreme (x^2)/(x^2+243)extreme points

\frac{x ^{2}}{x ^{2} + 243}

extreme f(x)=6sin^2(x)+6sin(x)extreme points

f (x) = 6 sin^{2} (x) + 6 sin (x)

extreme f(x)=3^2-6x-9=0 extreme points

f (x) = 3^{2} - 6 x - 9 = 0

Frequently Asked Questions (FAQ)

What is the extreme ln(x^2+4) ?
The extreme ln(x^2+4) is Minimum(0,2ln(2))