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Popular >

extreme y=(1/(x^2-4x-5))

Solution

extreme points

y = (\frac{1}{x ^{2} - 4 x - 5})

Solution

Maximum (2, - \frac{1}{9})

Solution steps

f^{'} (x) = - \frac{2 x - 4}{( x ^{2} - 4 x - 5 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 2,

Decreasing

: 2 < x < 5,

Decreasing

: 5 < x < \infty

Plug

x = 2

into

\frac{1}{x ^{2} - 4 x - 5} : - \frac{1}{9}

Maximum (2, - \frac{1}{9})

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Frequently Asked Questions (FAQ)

What is the extreme y=(1/(x^2-4x-5)) ?
The extreme y=(1/(x^2-4x-5)) is Maximum(2,-1/9)