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Popular >

extreme f(x)=2x^2-8x+2(0.5)

Solution

extreme points

f (x) = 2 x^{2} - 8 x + 2 (0.5)

Solution

Minimum (2, - 7)

Solution steps

f^{'} (x) = 4 x - 8

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

2 x^{2} - 8 x + 20.5 : - 7

Minimum (2, - 7)

Popular Examples

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f (x, y) = x^{3} - 12 x + y^{2} + 6 y + 14

extreme f(x)= 1/5 x^5-2/3 x^3+x extreme points

f (x) = \frac{1}{5} x^{5} - \frac{2}{3} x^{3} + x

extreme f(x)=| 1/16 x^3-4|extreme points

f (x) = \frac{1}{16} x^{3} - 4

extreme (sqrt(x-5))/4 extreme points

\frac{x - 5}{4}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2-8x+2(0.5) ?
The extreme f(x)=2x^2-8x+2(0.5) is Minimum(2,-7)