What is the extreme f(x)=-x^3+3x-11 ?

The extreme f(x)=-x^3+3x-11 is Minimum(-1,-13),Maximum(1,-9)

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extreme f(x)=-x^3+3x-11

extreme points

f (x) = - x^{3} + 3 x - 11

Minimum (- 1, - 13), Maximum (1, - 9)

Solution steps

f^{'} (x) = - 3 x^{2} + 3

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = - 1

into

- x^{3} + 3 x - 11 : - 13

Minimum (- 1, - 13)

Plug

x = 1

into

- x^{3} + 3 x - 11 : - 9

Maximum (1, - 9)

Minimum (- 1, - 13), Maximum (1, - 9)

f (x) = 2 x^{3} - 3 x^{2} - 4

f (x) = - 12 x^{3} + 2 x^{2} - 3

f (x) = x^{3} - 2 x^{2} - 15 x + 10 [- 2]

f (x, y) = x^{2} - y^{2} + x y - 5 x

y = \frac{1}{2} x^{2} + (\frac{14 - 3 x}{4})^{2}

What is the extreme f(x)=-x^3+3x-11 ?
The extreme f(x)=-x^3+3x-11 is Minimum(-1,-13),Maximum(1,-9)