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Popular >

extreme s(t)=-t^2+5t+1

Solution

extreme points

s (t) = - t^{2} + 5 t + 1

Solution

Maximum (\frac{5}{2}, \frac{29}{4})

Solution steps

f^{'} (t) = - 2 t + 5

Find intervals:

Increasing

: - \infty < t < \frac{5}{2},

Decreasing

: \frac{5}{2} < t < \infty

Plug

t = \frac{5}{2}

into

- t^{2} + 5 t + 1 : \frac{29}{4}

Maximum (\frac{5}{2}, \frac{29}{4})

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Frequently Asked Questions (FAQ)

What is the extreme s(t)=-t^2+5t+1 ?
The extreme s(t)=-t^2+5t+1 is Maximum(5/2 , 29/4)