What is the extreme f(x)=21-12x-(12)/x ?

The extreme f(x)=21-12x-(12)/x is Minimum(-1,45),Maximum(1,-3)

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extreme f(x)=21-12x-(12)/x

extreme points

f (x) = 21 - 12 x - \frac{12}{x}

Minimum (- 1, 45), Maximum (1, - 3)

Solution steps

f^{'} (x) = \frac{12}{x ^{2}} - 12

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 0,

Increasing

: 0 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = - 1

into

21 - 12 x - \frac{12}{x} : 45

Minimum (- 1, 45)

Plug

x = 1

into

21 - 12 x - \frac{12}{x} : - 3

Maximum (1, - 3)

Minimum (- 1, 45), Maximum (1, - 3)

f (x) = \frac{2 x - 1}{x}

y = (\frac{x}{x + 5})

f (x) = 2 x^{2} - 4 x - 6

f (x, y) = 2 x^{2} + 4 x y

f (x) = \frac{( 9 - x ^{2} )}{( 2 x + 6 )}

What is the extreme f(x)=21-12x-(12)/x ?
The extreme f(x)=21-12x-(12)/x is Minimum(-1,45),Maximum(1,-3)