What is the extreme f(x)=6x^3-18x-4 ?

The extreme f(x)=6x^3-18x-4 is Maximum(-1,8),Minimum(1,-16)

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extreme f(x)=6x^3-18x-4

extreme points

f (x) = 6 x^{3} - 18 x - 4

Maximum (- 1, 8), Minimum (1, - 16)

Solution steps

f^{'} (x) = 18 x^{2} - 18

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

6 x^{3} - 18 x - 4 : 8

Maximum (- 1, 8)

Plug

x = 1

into

6 x^{3} - 18 x - 4 : - 16

Minimum (1, - 16)

Maximum (- 1, 8), Minimum (1, - 16)

f (x, y) = e^{x + y + 8}

f (x, y) = 2 x^{2} + 2 x y + y^{2} + 2 x - 4

f (x) = 21 - 4 x - \frac{4}{x}

- x^{3} + 3 x - 4

y = (x^{2} - 4)

What is the extreme f(x)=6x^3-18x-4 ?
The extreme f(x)=6x^3-18x-4 is Maximum(-1,8),Minimum(1,-16)