What is the extreme f(x)=4x^3-4x^2-4x+7 ?

The extreme f(x)=4x^3-4x^2-4x+7 is Maximum(-1/3 , 209/27),Minimum(1,3)

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extreme f(x)=4x^3-4x^2-4x+7

extreme points

f (x) = 4 x^{3} - 4 x^{2} - 4 x + 7

Maximum (- \frac{1}{3}, \frac{209}{27}), Minimum (1, 3)

Solution steps

f^{'} (x) = 12 x^{2} - 8 x - 4

Find intervals:

Increasing

: - \infty < x < - \frac{1}{3},

Decreasing

: - \frac{1}{3} < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - \frac{1}{3}

into

4 x^{3} - 4 x^{2} - 4 x + 7 : \frac{209}{27}

Maximum (- \frac{1}{3}, \frac{209}{27})

Plug

x = 1

into

4 x^{3} - 4 x^{2} - 4 x + 7 : 3

Minimum (1, 3)

Maximum (- \frac{1}{3}, \frac{209}{27}), Minimum (1, 3)

3.79254 E 84

y = \frac{4}{x} + x

x \cdot 4 - x^{2}

f (x) = 2 x^{2} - 15 x^{2} + 36 x + 10

\frac{x ^{3}}{x ^{2} - 3}

What is the extreme f(x)=4x^3-4x^2-4x+7 ?
The extreme f(x)=4x^3-4x^2-4x+7 is Maximum(-1/3 , 209/27),Minimum(1,3)