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Popular >

extreme y=(x+7)(x+3)

Solution

extreme points

y = (x + 7) (x + 3)

Solution

Minimum (- 5, - 4)

Solution steps

f^{'} (x) = 2 (x + 5)

Find intervals:

Decreasing

: - \infty < x < - 5,

Increasing

: - 5 < x < \infty

Plug

x = - 5

into

(x + 7) (x + 3) : - 4

Minimum (- 5, - 4)

Popular Examples

extreme f(x)=-3x^2+2x-4,1<= x<= 4 extreme points

f (x) = - 3 x^{2} + 2 x - 4, 1 \leq x \leq 4

extreme R(M)=M^2(1/2-M/3)extreme points

R (M) = M^{2} (\frac{1}{2} - \frac{M}{3})

extreme f(x)=8x^4-5x^3+x^2-2x+3 extreme points

f (x) = 8 x^{4} - 5 x^{3} + x^{2} - 2 x + 3

extreme f(x,y)=sqrt(400-81x^2-81y^2)extreme points

f (x, y) = 400 - 81 x^{2} - 81 y^{2}

extreme f(x)= 1/2 (x-2)^{-1/2}extreme points

f (x) = \frac{1}{2} (x - 2)^{- \frac{1}{2}}

Frequently Asked Questions (FAQ)

What is the extreme y=(x+7)(x+3) ?
The extreme y=(x+7)(x+3) is Minimum(-5,-4)