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Popular >

extreme x^4+2x^2

Solution

extreme points

x^{4} + 2 x^{2}

Solution

Minimum (0, 0)

Solution steps

f^{'} (x) = 4 x^{3} + 4 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{4} + 2 x^{2} : 0

Minimum (0, 0)

Popular Examples

extreme f(x)= x/(x^2+25),-7<= x<= 7 extreme points

f (x) = \frac{x}{x ^{2} + 25}, - 7 \leq x \leq 7

extreme f(x)=4x^2+(3000)/x extreme points

f (x) = 4 x^{2} + \frac{3000}{x}

extreme f(x)=-3x^2-y^2+2xy-3x-y extreme points

f (x) = - 3 x^{2} - y^{2} + 2 x y - 3 x - y

extreme f(x,y)=x^3+8y^3-12xy extreme points

f (x, y) = x^{3} + 8 y^{3} - 12 x y

extreme f(x)=4xe^{-4x+1}extreme points

f (x) = 4 x e^{- 4 x + 1}

Frequently Asked Questions (FAQ)

What is the extreme x^4+2x^2 ?
The extreme x^4+2x^2 is Minimum(0,0)