What is the extreme f(x,y)=x^2-y^2-20x+2y+8 ?

The extreme f(x,y)=x^2-y^2-20x+2y+8 is Saddle(10,1)

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extreme f(x,y)=x^2-y^2-20x+2y+8

extreme points

f (x, y) = x^{2} - y^{2} - 20 x + 2 y + 8

Saddle (10, 1)

Solution steps

Find the critical points:

(10, 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = - 4

Check the sign of at each critical point

Check critical point

(10, 1) :

Saddle

Saddle (10, 1)

f (x, y) = \frac{x y}{x ^{2} + 1}

x^{4} + 2 x^{3} + 1

f (x, y) = x^{2} + 3 y^{2} - 2 x y + 10 x - 2 y + 4

- x \cdot e^{- x}

\frac{7 x}{x ^{2} - 49}

What is the extreme f(x,y)=x^2-y^2-20x+2y+8 ?
The extreme f(x,y)=x^2-y^2-20x+2y+8 is Saddle(10,1)