What is the extreme-(5e^{4x})/(x-4) ?

The extreme-(5e^{4x})/(x-4) is Maximum(17/4 ,-20e^{17})

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extreme-(5e^{4x})/(x-4)

extreme points

- \frac{5 e ^{4 x}}{x - 4}

Maximum (\frac{17}{4}, - 20 e^{17})

Solution steps

f^{'} (x) = - \frac{5 ( 4 e ^{4 x} x - 17 e ^{4 x} )}{( x - 4 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 4,

Increasing

: 4 < x < \frac{17}{4},

Decreasing

: \frac{17}{4} < x < \infty

Plug

x = \frac{17}{4}

into

- \frac{5 e ^{4 x}}{x - 4} : - 20 e^{17}

Maximum (\frac{17}{4}, - 20 e^{17})

f (x, y) = x - k y

f (x) = \frac{x + 3}{x ^{2} - 2 x - 15}

f (x) = x^{2} (e^{- x^{2}})

Z (p, q) = p^{2} + q^{2}

f (x) = x^{3} + 4 x^{2} + 10

What is the extreme-(5e^{4x})/(x-4) ?
The extreme-(5e^{4x})/(x-4) is Maximum(17/4 ,-20e^{17})