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Popular >

extreme f(x)=-2x^3-13

Solution

extreme points

f (x) = - 2 x^{3} - 13

Solution

Saddle (0, - 13)

Solution steps

f^{'} (x) = - 6 x^{2}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = 0

into

- 2 x^{3} - 13 : - 13

Saddle (0, - 13)

Popular Examples

extreme f(x)=9-4x-3x^2,-2<= x<= 1 extreme points

f (x) = 9 - 4 x - 3 x^{2}, - 2 \leq x \leq 1

extreme f(x)=3x^2+12x-9 extreme points

f (x) = 3 x^{2} + 12 x - 9

extreme f(x)=395x^2-3160x^3 extreme points

f (x) = 395 x^{2} - 3160 x^{3}

extreme e^{x-1}extreme points

e^{x - 1}

extreme (8x^3)/3+15x^2-8x,-5<= x<= 1 extreme points

\frac{8 x ^{3}}{3} + 15 x^{2} - 8 x, - 5 \leq x \leq 1

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-2x^3-13 ?
The extreme f(x)=-2x^3-13 is Saddle(0,-13)