en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=3x^2+12x+7/8

Solution

extreme points

f (x) = 3 x^{2} + 12 x + \frac{7}{8}

Solution

Minimum (- 2, - \frac{89}{8})

Solution steps

f^{'} (x) = 6 x + 12

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 2

into

3 x^{2} + 12 x + \frac{7}{8} : - \frac{89}{8}

Minimum (- 2, - \frac{89}{8})

Popular Examples

extreme f(x)=(x^3-64)^4 extreme points

f (x) = (x^{3} - 64)^{4}

extreme f(x,y)=7x^2+7xy+10y^2+7xy^2+4x^2y extreme points

f (x, y) = 7 x^{2} + 7 x y + 10 y^{2} + 7 x y^{2} + 4 x^{2} y

extreme 3/(sqrt(x))-1 extreme points

\frac{3}{x} - 1

extreme (2x)/(9-x^2)extreme points

\frac{2 x}{9 - x ^{2}}

extreme y(θ)=tan^2(θ)-1,-pi/2 <θ< pi/2 extreme points

y (θ) = tan^{2} (θ) - 1, - \frac{π}{2} < θ < \frac{π}{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=3x^2+12x+7/8 ?
The extreme f(x)=3x^2+12x+7/8 is Minimum(-2,-89/8)