What is the extreme f(x)=33e^{-6x}-30e^{-5x} ?

The extreme f(x)=33e^{-6x}-30e^{-5x} is Minimum(ln(33/25),-48828125/39135393)

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extreme f(x)=33e^{-6x}-30e^{-5x}

extreme points

f (x) = 33 e^{- 6 x} - 30 e^{- 5 x}

Minimum (ln (\frac{33}{25}), - \frac{48828125}{39135393})

Solution steps

f^{'} (x) = 6 e^{- 6 x} (- 33 + 25 e^{x})

Find intervals:

Decreasing

: - \infty < x < ln (\frac{33}{25}),

Increasing

: ln (\frac{33}{25}) < x < \infty

Plug

x = ln (\frac{33}{25})

into

33 e^{- 6 x} - 30 e^{- 5 x} : - \frac{48828125}{39135393}

Minimum (ln (\frac{33}{25}), - \frac{48828125}{39135393})

f (x) = 1617 x - 0.11 x^{3}

f (x) = x^{(6)} - x^{(3)} + 3

f (x) = 5 - 6 x - 4 x^{2}

f (x) = 0.002 x^{3} + 9 x + 7626

f (x, y) = (1 - x y)

What is the extreme f(x)=33e^{-6x}-30e^{-5x} ?
The extreme f(x)=33e^{-6x}-30e^{-5x} is Minimum(ln(33/25),-48828125/39135393)