What is the extreme f(x)=x^3-15x^2+27x-8 ?

The extreme f(x)=x^3-15x^2+27x-8 is Maximum(1,5),Minimum(9,-251)

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extreme f(x)=x^3-15x^2+27x-8

extreme points

f (x) = x^{3} - 15 x^{2} + 27 x - 8

Maximum (1, 5), Minimum (9, - 251)

Solution steps

f^{'} (x) = 3 x^{2} - 30 x + 27

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 9,

Increasing

: 9 < x < \infty

Plug

x = 1

into

x^{3} - 15 x^{2} + 27 x - 8 : 5

Maximum (1, 5)

Plug

x = 9

into

x^{3} - 15 x^{2} + 27 x - 8 : - 251

Minimum (9, - 251)

Maximum (1, 5), Minimum (9, - 251)

f (x) = 2 x + 37 x^{\frac{2}{37}}

f (x, y) = 11 - 7 x + 9 y

y = 9 x^{2}

f (x) = x^{3} - 17 x^{2} - 24 x

y = \frac{x ^{2} - x - 2}{x - 2}

What is the extreme f(x)=x^3-15x^2+27x-8 ?
The extreme f(x)=x^3-15x^2+27x-8 is Maximum(1,5),Minimum(9,-251)