What is the extreme (0.002x^3+9x+7626)/x ?

The extreme (0.002x^3+9x+7626)/x is Minimum(5\sqrt[3]{15252},101.25199…)

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extreme (0.002x^3+9x+7626)/x

extreme points

\frac{0.002 x ^{3} + 9 x + 7626}{x}

Solution steps

f^{'} (x) = \frac{0.004 x ^{3} - 7626}{x ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < 123.99731 \dots,

Increasing

: 123.99731 \dots < x < \infty

Plug

into

\frac{0.002 x ^{3} + 9 x + 7626}{x} : 101.25199 \dots

3 x^{4} - 4 x^{3} + 6

x^{- 2} - 13 x^{- 1}

f (x) = 4 x - 24 x - 4

f (x) = [∣ x ∣]

x^{3} - 12 x - 3

What is the extreme (0.002x^3+9x+7626)/x ?
The extreme (0.002x^3+9x+7626)/x is Minimum(5\sqrt[3]{15252},101.25199…)