What is the extreme f(x)=2x^3+9x^2-60x+1 ?

The extreme f(x)=2x^3+9x^2-60x+1 is Maximum(-5,276),Minimum(2,-67)

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extreme f(x)=2x^3+9x^2-60x+1

extreme points

f (x) = 2 x^{3} + 9 x^{2} - 60 x + 1

Maximum (- 5, 276), Minimum (2, - 67)

Solution steps

f^{'} (x) = 6 x^{2} + 18 x - 60

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 5

into

2 x^{3} + 9 x^{2} - 60 x + 1 : 276

Maximum (- 5, 276)

Plug

x = 2

into

2 x^{3} + 9 x^{2} - 60 x + 1 : - 67

Minimum (2, - 67)

Maximum (- 5, 276), Minimum (2, - 67)

f (x) = 2 x^{3} + 9 x^{2} - 60 x + 8

y = x^{\frac{4}{7}} (x^{2} - 2)

f (θ) = 2 θ - 3 sin (θ), 0 \leq θ \leq π

f (x) = x (x - 3)^{2} (x + 1)^{4}

x^{3} - 12 x^{2} + 45 x + 6

What is the extreme f(x)=2x^3+9x^2-60x+1 ?
The extreme f(x)=2x^3+9x^2-60x+1 is Maximum(-5,276),Minimum(2,-67)