What is the extreme h(x)=4-3x^2,(-2,1) ?

The extreme h(x)=4-3x^2,(-2,1) is Maximum(0,4)

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extreme h(x)=4-3x^2,(-2,1)

extreme points

h (x) = 4 - 3 x^{2}, (- 2, 1)

Maximum (0, 4)

Solution steps

Find the critical points:

x = 0

Domain of

4 - 3 x^{2}, (- 2, 1) : - 2 < x < 1

Find intervals:

Increasing

: - 2 < x < 0,

Decreasing

: 0 < x < 1

Plug the extreme point

x = 0

into

4 - 3 x^{2} \Rightarrow y = 4

Maximum (0, 4)

f (x) = - 5 + 5 x - x^{2}

\frac{3 + x}{9 - x}, - 9 \leq x \leq 0

(x - 1)^{2} (2 x - 8)

y = 4 x^{\frac{3}{4}} - x (256)

f (x) = 64 - x^{2}, - 8 \leq x \leq 8

What is the extreme h(x)=4-3x^2,(-2,1) ?
The extreme h(x)=4-3x^2,(-2,1) is Maximum(0,4)