en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)= 4/(4x^2-1)+b

Solution

extreme points

f (x) = \frac{4}{4 x ^{2} - 1} + b

Solution

Maximum (0, - 4 + b)

Solution steps

f^{'} (x) = - \frac{32 x}{( 2 x + 1 ) ^{2} ( 2 x - 1 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - \frac{1}{2},

Increasing

: - \frac{1}{2} < x < 0,

Decreasing

: 0 < x < \frac{1}{2},

Decreasing

: \frac{1}{2} < x < \infty

Plug

x = 0

into

\frac{4}{4 x ^{2} - 1} + b : - 4 + b

Maximum (0, - 4 + b)

Popular Examples

extreme f(x)=3x^2-36x+81 extreme points

f (x) = 3 x^{2} - 36 x + 81

extreme K(r,s)=3r-4s extreme points

K (r, s) = 3 r - 4 s

extreme f(9)= t/(t-4)extreme points

f (9) = \frac{t}{t - 4}

extreme f(x,y)=3x^2-2xy+y^2 extreme points

f (x, y) = 3 x^{2} - 2 x y + y^{2}

extreme 2x^2+8x-1 extreme points

2 x^{2} + 8 x - 1

Frequently Asked Questions (FAQ)

What is the extreme f(x)= 4/(4x^2-1)+b ?
The extreme f(x)= 4/(4x^2-1)+b is Maximum(0,-4+b)