What is the extreme f(x,y)=x^{3/4}y^{1/4} ?

The extreme f(x,y)=x^{3/4}y^{1/4} is None

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extreme f(x,y)=x^{3/4}y^{1/4}

extreme points

f (x, y) = x^{\frac{3}{4}} y^{\frac{1}{4}}

None

Solution steps

Find the critical points:

None

x^{\frac{3}{4}} y^{\frac{1}{4}}

has no critical points, therefore there are no extreme points

None

x^{3} - 3 x^{2} + 6 x - 6

f (x) = x^{(\frac{2}{3})} (x - 3)

f (x) = 6 x^{3} + 54 x^{2} + 144 x + 54

(x - 7) (x^{2} - 14 x - 98)

y = (4 - x) \cdot 4^{x}

What is the extreme f(x,y)=x^{3/4}y^{1/4} ?
The extreme f(x,y)=x^{3/4}y^{1/4} is None