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Popular >

extreme f(x)=-7+12x-3x^2

Solution

extreme points

f (x) = - 7 + 12 x - 3 x^{2}

Solution

Maximum (2, 5)

Solution steps

f^{'} (x) = - 6 x + 12

Find intervals:

Increasing

: - \infty < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = 2

into

- 7 + 12 x - 3 x^{2} : 5

Maximum (2, 5)

Popular Examples

extreme 2x^3-6 extreme points

2 x^{3} - 6

extreme f(x)=(x^2-7)(x^2-6)(x^2+4)extreme points

f (x) = (x^{2} - 7) (x^{2} - 6) (x^{2} + 4)

extreme f(x)=(x-3)^{4/3},-7<= x<= 7 extreme points

f (x) = (x - 3)^{\frac{4}{3}}, - 7 \leq x \leq 7

extreme 2x^3-2x^2-x-9 extreme points

2 x^{3} - 2 x^{2} - x - 9

extreme y=(x^2)/2-3x+7/2 extreme points

y = \frac{x ^{2}}{2} - 3 x + \frac{7}{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-7+12x-3x^2 ?
The extreme f(x)=-7+12x-3x^2 is Maximum(2,5)