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Popular >

extreme 2x^3-6

Solution

extreme points

2 x^{3} - 6

Solution

Saddle (0, - 6)

Solution steps

f^{'} (x) = 6 x^{2}

Find intervals:

Increasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

2 x^{3} - 6 : - 6

Saddle (0, - 6)

Popular Examples

extreme f(x)=(x^2-7)(x^2-6)(x^2+4)extreme points

f (x) = (x^{2} - 7) (x^{2} - 6) (x^{2} + 4)

extreme f(x)=(x-3)^{4/3},-7<= x<= 7 extreme points

f (x) = (x - 3)^{\frac{4}{3}}, - 7 \leq x \leq 7

extreme 2x^3-2x^2-x-9 extreme points

2 x^{3} - 2 x^{2} - x - 9

extreme y=(x^2)/2-3x+7/2 extreme points

y = \frac{x ^{2}}{2} - 3 x + \frac{7}{2}

extreme P(x,y)=-4x+5y-x^2+2xy-7y^2+9 extreme points

P (x, y) = - 4 x + 5 y - x^{2} + 2 x y - 7 y^{2} + 9

Frequently Asked Questions (FAQ)

What is the extreme 2x^3-6 ?
The extreme 2x^3-6 is Saddle(0,-6)