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Popular >

extreme f(x)=-2x^3+12

Solution

extreme points

f (x) = - 2 x^{3} + 12

Solution

Saddle (0, 12)

Solution steps

f^{'} (x) = - 6 x^{2}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = 0

into

- 2 x^{3} + 12 : 12

Saddle (0, 12)

Popular Examples

extreme f(x)=-2x^2+3x-4 extreme points

f (x) = - 2 x^{2} + 3 x - 4

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f (x) = \frac{2 + 4 x ^{2}}{1 - 3 x}

extreme f(x)=6x+(24)/(x^2)+5,x>0 extreme points

f (x) = 6 x + \frac{24}{x ^{2}} + 5, x > 0

extreme f(x)=-5x^{+30x+1}extreme points

f (x) = - 5 x^{+ 30 x + 1}

extreme f(x,y)=3x-5y-2 extreme points

f (x, y) = 3 x - 5 y - 2

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-2x^3+12 ?
The extreme f(x)=-2x^3+12 is Saddle(0,12)