What is the extreme f(x)=-0.000003x^3+9x-300 ?

The extreme f(x)=-0.000003x^3+9x-300 is Minimum(-1000,-6300),Maximum(1000,5700)

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extreme f(x)=-0.000003x^3+9x-300

extreme points

f (x) = - 0.000003 x^{3} + 9 x - 300

Minimum (- 1000, - 6300), Maximum (1000, 5700)

Solution steps

f^{'} (x) = - 0.000009 x^{2} + 9

Find intervals:

Decreasing

: - \infty < x < - 1000,

Increasing

: - 1000 < x < 1000,

Decreasing

: 1000 < x < \infty

Plug

x = - 1000

into

- 0.000003 x^{3} + 9 x - 300 : - 6300

Minimum (- 1000, - 6300)

Plug

x = 1000

into

- 0.000003 x^{3} + 9 x - 300 : 5700

Maximum (1000, 5700)

Minimum (- 1000, - 6300), Maximum (1000, 5700)

\frac{x - 5}{x - 7}

f (x, y) = y^{3} - y x - x^{2} y^{2} + x^{3}

4 x^{2} - 400 x + 22500

\frac{x ( x - 3 ) ^{2}}{2}

f (x) = - 0.1 t^{2} + 1.2 t + 98.6

What is the extreme f(x)=-0.000003x^3+9x-300 ?
The extreme f(x)=-0.000003x^3+9x-300 is Minimum(-1000,-6300),Maximum(1000,5700)