What is the extreme f(x)=-0.1t^2+1.2t+98.7 ?

The extreme f(x)=-0.1t^2+1.2t+98.7 is Maximum(6,102.3)

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extreme f(x)=-0.1t^2+1.2t+98.7

extreme points

f (x) = - 0.1 t^{2} + 1.2 t + 98.7

Maximum (6, 102.3)

Solution steps

f^{'} (t) = - 0.2 t + 1.2

Find intervals:

Increasing

: - \infty < t < 6,

Decreasing

: 6 < t < \infty

Plug

t = 6

into

- 0.1 t^{2} + 1.2 t + 98.7 : 102.3

Maximum (6, 102.3)

x^{4} - 2 x^{2} + 1 [- 2.2]

P (a, b) = a + b

f (x) = 3 x^{3} + 92 x^{2} - 54 x + 1

y = - \frac{1}{3} e^{- 3 x} x - \frac{10}{9} e^{- 3 x}

f (y) = 6 x y - 6 y

What is the extreme f(x)=-0.1t^2+1.2t+98.7 ?
The extreme f(x)=-0.1t^2+1.2t+98.7 is Maximum(6,102.3)