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Popular >

extreme y=2(x^2-7x+10)

Solution

extreme points

y = 2 (x^{2} - 7 x + 10)

Solution

Minimum (\frac{7}{2}, - \frac{9}{2})

Solution steps

f^{'} (x) = 2 (2 x - 7)

Find intervals:

Decreasing

: - \infty < x < \frac{7}{2},

Increasing

: \frac{7}{2} < x < \infty

Plug

x = \frac{7}{2}

into

2 (x^{2} - 7 x + 10) : - \frac{9}{2}

Minimum (\frac{7}{2}, - \frac{9}{2})

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Frequently Asked Questions (FAQ)

What is the extreme y=2(x^2-7x+10) ?
The extreme y=2(x^2-7x+10) is Minimum(7/2 ,-9/2)