en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=2x^2-12x+7

Solution

extreme points

f (x) = 2 x^{2} - 12 x + 7

Solution

Minimum (3, - 11)

Solution steps

f^{'} (x) = 4 x - 12

Find intervals:

Decreasing

: - \infty < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 3

into

2 x^{2} - 12 x + 7 : - 11

Minimum (3, - 11)

Popular Examples

extreme f(x)=((x-7)(x+9))+64 extreme points

f (x) = ((x - 7) (x + 9)) + 64

extreme f(x)=(6x^3)/(x-4)extreme points

f (x) = \frac{6 x ^{3}}{x - 4}

extreme f(x)=2x^5+10x^4+x^3-10 extreme points

f (x) = 2 x^{5} + 10 x^{4} + x^{3} - 10

extreme f(4)=e^{2x^2+4y^2-16x}extreme points

f (4) = e^{2 x^{2} + 4 y^{2} - 16 x}

extreme (4x+y-2)^2+(x+y-1)^2+(4-4x-y)^2 extreme points

(4 x + y - 2)^{2} + (x + y - 1)^{2} + (4 - 4 x - y)^{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2-12x+7 ?
The extreme f(x)=2x^2-12x+7 is Minimum(3,-11)