What is the extreme f(x,y)=-2x^2+16x-y^2+6y-30 ?

The extreme f(x,y)=-2x^2+16x-y^2+6y-30 is Maximum(4,3)

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extreme f(x,y)=-2x^2+16x-y^2+6y-30

extreme points

f (x, y) = - 2 x^{2} + 16 x - y^{2} + 6 y - 30

Maximum (4, 3)

Solution steps

Find the critical points:

(4, 3)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = 8

Check the sign of at each critical point

Check critical point

(4, 3) :

Maximum

Maximum (4, 3)

f (x) = 2 x - \frac{1}{2} (\frac{x}{50})^{2} - 1000

f (x, y) = - 6 x^{2} - 3 x y - 7 y^{2} - 90 x + 4 y + 8

f (x) = (x + 1)^{7} - 7 x - 2

f (x) = 7 x e^{- x}

f (x) = 2 - 3 x + x^{3}

What is the extreme f(x,y)=-2x^2+16x-y^2+6y-30 ?
The extreme f(x,y)=-2x^2+16x-y^2+6y-30 is Maximum(4,3)