What is the extreme f(x)=2x^3-7x^2+4x ?

The extreme f(x)=2x^3-7x^2+4x is Maximum(1/3 , 17/27),Minimum(2,-4)

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extreme f(x)=2x^3-7x^2+4x

extreme points

f (x) = 2 x^{3} - 7 x^{2} + 4 x

Maximum (\frac{1}{3}, \frac{17}{27}), Minimum (2, - 4)

Solution steps

f^{'} (x) = 6 x^{2} - 14 x + 4

Find intervals:

Increasing

: - \infty < x < \frac{1}{3},

Decreasing

: \frac{1}{3} < x < 2,

Increasing

: 2 < x < \infty

Plug

x = \frac{1}{3}

into

2 x^{3} - 7 x^{2} + 4 x : \frac{17}{27}

Maximum (\frac{1}{3}, \frac{17}{27})

Plug

x = 2

into

2 x^{3} - 7 x^{2} + 4 x : - 4

Minimum (2, - 4)

Maximum (\frac{1}{3}, \frac{17}{27}), Minimum (2, - 4)

x^{4} + 2 x^{3} + x^{2} + x + 1

f (x) = x^{2} - 4 x y + y^{2} - 4

f (x) = 15 x^{2} - 60 x + 25

f (x) = 10 sin (2 x), (- 2 π, 2 π)

What is the extreme f(x)=2x^3-7x^2+4x ?
The extreme f(x)=2x^3-7x^2+4x is Maximum(1/3 , 17/27),Minimum(2,-4)