What is the extreme f(x,y)=2xy-32x+64y ?

The extreme f(x,y)=2xy-32x+64y is Saddle(-32,16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x,y)=2xy-32x+64y

extreme points

f (x, y) = 2 x y - 32 x + 64 y

Saddle (- 32, 16)

Solution steps

Find the critical points:

(- 32, 16)

\frac{\partial ^{2} f}{\partial x ^{2}} = 0

D (x, y) = - 4

Check the sign of at each critical point

Check critical point

(- 32, 16) :

Saddle

Saddle (- 32, 16)

f (x) = 6 x y - \frac{1}{2} (x^{4} + y^{4}) - 2

f (x, y) = - x^{2} + 2 y^{2}

f (x) = x^{4} - 2 x^{2} + y^{3} - 27 y - 15

f (x) = 0.01 x^{2} - 0.2 x + 8

f (x) = - 2500 x^{2} + 45000 + 1360000

What is the extreme f(x,y)=2xy-32x+64y ?
The extreme f(x,y)=2xy-32x+64y is Saddle(-32,16)