What is the extreme f(x)=((x^2))/(x-2) ?

The extreme f(x)=((x^2))/(x-2) is Maximum(0,0),Minimum(4,8)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=((x^2))/(x-2)

extreme points

f (x) = \frac{( x ^{2} )}{x - 2}

Maximum (0, 0), Minimum (4, 8)

Solution steps

f^{'} (x) = \frac{x ^{2} - 4 x}{( x - 2 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 2,

Decreasing

: 2 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 0

into

\frac{x ^{2}}{x - 2} : 0

Maximum (0, 0)

Plug

x = 4

into

\frac{x ^{2}}{x - 2} : 8

Minimum (4, 8)

Maximum (0, 0), Minimum (4, 8)

f (x) = \frac{( 7 ln ( x ) + 4 )}{x}

f (x) = \frac{24}{x} + 4 π r^{2}

f (x) = x^{3} - 36 x^{2} + 324 x - 3280.5

h (v, t) = v t - 5 t^{2}

f (x) = \frac{( 3 e ^{x} )}{x ^{3}}

What is the extreme f(x)=((x^2))/(x-2) ?
The extreme f(x)=((x^2))/(x-2) is Maximum(0,0),Minimum(4,8)